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-2x^2-3x=2x^2+17
We move all terms to the left:
-2x^2-3x-(2x^2+17)=0
We get rid of parentheses
-2x^2-2x^2-3x-17=0
We add all the numbers together, and all the variables
-4x^2-3x-17=0
a = -4; b = -3; c = -17;
Δ = b2-4ac
Δ = -32-4·(-4)·(-17)
Δ = -263
Delta is less than zero, so there is no solution for the equation
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